นิพจน์ 7: "O" Subscript, 1 , Baseline equals "P" Subscript, 1 , Baseline left parenthesis, "t" , right parenthesisO1=P1t
โดเมน t ค่าต่ำสุด: negative 20−20
less than or equal to "t" less than or equal to≤t≤
โดเมน t ค่าสูงสุด: 00
7
นิพจน์ 8: "O" Subscript, 2 , Baseline equals "P" Subscript, 2 , Baseline left parenthesis, "t" , right parenthesisO2=P2t
โดเมน t ค่าต่ำสุด: negative 20−20
less than or equal to "t" less than or equal to≤t≤
โดเมน t ค่าสูงสุด: 00
8
นิพจน์ 9: "x" Subscript, "a" , Baseline equals negative 5xa=−5
negative 8−8
00
9
นิพจน์ 10: round left parenthesis, "a" Subscript, "b" "s" , Baseline left parenthesis, "P" Subscript, 1 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesis minus "P" Subscript, 2 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesis , right parenthesis , 2 , right parenthesisroundabsP1xa−P2xa,2
equals=
3.53.5
10
นิพจน์ 11: "P" Subscript, 1 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesisP1xa
equals=
left parenthesis, negative 2.5 , 1.9 3 6 4 9 1 6 7 , 0.5 , right parenthesis−2.5,1.93649167,0.5
11
นิพจน์ 12: "P" Subscript, 2 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesisP2xa
equals=
left parenthesis, negative 5 , 0 , negative 1 , right parenthesis−5,0,−1
12
นิพจน์ 13: "P" Subscript, 1 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesis left parenthesis, 1 minus "t" , right parenthesis plus "P" Subscript, 2 , Baseline left parenthesis, "x" Subscript, "a" , Baseline , right parenthesis "t"P1xa1−t+P2xat
00
โดเมน t ค่าต่ำสุด:
less than or equal to "t" less than or equal to≤t≤
