You might need to adjust range for b and t to match your curve.
6
式7: "b" equals 0b=0
00
2 pi2π
7
式8: left parenthesis, "x" Subscript, 1 , Baseline left parenthesis, "t" , right parenthesis , "y" Subscript, 1 , Baseline left parenthesis, "t" , right parenthesis , "z" Subscript, 1 , Baseline left parenthesis, "t" , right parenthesis , right parenthesisx1t,y1t,z1t
定義域t最小値: 00
less than or equal to "t" less than or equal to≤t≤
定義域t最大値: 2 pi2π
8
式9: "p" equals left parenthesis, "x" Subscript, 1 , Baseline left parenthesis, "b" , right parenthesis , "y" Subscript, 1 , Baseline left parenthesis, "b" , right parenthesis , "z" Subscript, 1 , Baseline left parenthesis, "b" , right parenthesis , right parenthesisp=x1b,y1b,z1b
equals=
left parenthesis, 1 , 0 , 0 , right parenthesis1,0,0
9
式10: "d" equals left parenthesis, "x" Subscript, 1 , Baseline prime left parenthesis, "b" , right parenthesis , "y" Subscript, 1 , Baseline prime left parenthesis, "b" , right parenthesis , "z" Subscript, 1 , Baseline prime left parenthesis, "b" , right parenthesis , right parenthesisd=x1′b,y1′b,z1′b
equals=
left parenthesis, 0 , 1 , 0 , right parenthesis0,1,0
10
式11: vector left parenthesis, "p" , "p" plus "d" , right parenthesisvectorp,p+d
