We would like to trace I(X) = ( [-10...,10] , 0 ) but we can't have list of lists. We could solve I(x).x is integer via mod()=0, but there are precision issues. So we display epsilon around a value.
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Expression 17: "I" left parenthesis, "x" , right parenthesis equals absolute value left parenthesis, mod left parenthesis, "I" Subscript, "n" "v" "e" "r" "s" "i" "o" "n" , Baseline left parenthesis, "x" , right parenthesis , 1 , right parenthesis minus .5 , right parenthesisIx=absmodInversionx,1−.5
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Expression 18: min left parenthesis, "I" left parenthesis, "X" , right parenthesis left bracket, 1 , right bracket , "I" left parenthesis, "X" , right parenthesis left bracket, 2 , right bracket , right parenthesis less than or equal to .0 2minIX1,IX2≤.02
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Expression 19: left bracket, negative 30...3 0 , right bracket equals "I" Subscript, "n" "v" "e" "r" "s" "i" "o" "n" , Baseline left parenthesis, "X" , right parenthesis left bracket, 1 , right bracket−30...30=InversionX1
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Expression 20: left bracket, negative 30...3 0 , right bracket equals "I" Subscript, "n" "v" "e" "r" "s" "i" "o" "n" , Baseline left parenthesis, "X" , right parenthesis left bracket, 2 , right bracket−30...30=InversionX2