Cir-lin-skæring (opgave)

Uttryck 24: "g" Subscript, "h" "a" "l" "v" , Baseline equals StartRoot, 9 squared minus "h" squared , EndRoot

equals

7.6 8 4 3 2 0 4 3 1 1

Retningsvektoren bestemmes:

Uttryck 26: left parenthesis, "x" Subscript, "r" , Baseline left parenthesis, "t" , right parenthesis , "y" Subscript, "r" , Baseline left parenthesis, "t" , right parenthesis , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Uttryck 27: "x" Subscript, "r" , Baseline left parenthesis, "t" , right parenthesis equals "x" Subscript, 3 , Baseline minus 5 "t"

Uttryck 28: "y" Subscript, "r" , Baseline left parenthesis, "t" , right parenthesis equals "y" Subscript, 3 , Baseline plus 4 "t"

Hjælpelinjer

Uttryck 30: left parenthesis, "x" Subscript, 3 , Baseline minus 5 "t" , "y" Subscript, 3 , Baseline , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Uttryck 31: left parenthesis, "x" Subscript, 3 , Baseline minus 5 , "y" Subscript, 3 , Baseline plus 4 "t" , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Skalafaktoren bestemmes:

Uttryck 33: left parenthesis, left parenthesis, negative 5 , right parenthesis "S" Subscript, "F" , Baseline , right parenthesis squared plus left parenthesis, 4 "S" Subscript, "F" , Baseline , right parenthesis squared equals "g" squared

Uttryck 34: left parenthesis, negative 5 , right parenthesis squared "S" squared plus 4 squared "S" squared equals "g" squared

Uttryck 35: left parenthesis, left parenthesis, negative 5 , right parenthesis squared plus 4 squared , right parenthesis "S" squared equals "g" squared

Uttryck 36: "S" squared equals StartFraction, "g" squared Over left parenthesis, negative 5 , right parenthesis squared plus 4 squared , EndFraction

Uttryck 37: "S" Subscript, "F" , Baseline equals StartRoot, StartFraction, "g" squared Over left parenthesis, negative 5 , right parenthesis squared plus 4 squared , EndFraction , EndRoot

equals

1.2 0 0 0 8 9 2 2 9 2 8

Dermed er rødderne givet ved:

Uttryck 39: "x" Subscript, 1 , Baseline equals "x" Subscript, "r" , Baseline left parenthesis, "S" Subscript, "F" , Baseline , right parenthesis

equals

negative 6.9 2 7 2 7 5 4 1 4 7

Uttryck 40: "y" Subscript, 1 , Baseline equals "y" Subscript, "r" , Baseline left parenthesis, "S" Subscript, "F" , Baseline , right parenthesis

equals

4.1 4 1 8 2 0 3 3 1 7 6

Uttryck 41: "x" Subscript, 2 , Baseline equals "x" Subscript, "r" , Baseline left parenthesis, negative "S" Subscript, "F" , Baseline , right parenthesis

equals

5.0 7 3 6 1 6 8 7 8 1 2

Uttryck 42: "y" Subscript, 2 , Baseline equals "y" Subscript, "r" , Baseline left parenthesis, negative "S" Subscript, "F" , Baseline , right parenthesis

equals

negative 5.4 5 8 8 9 3 5 0 2 4 9

Højde og radiusser:

Uttryck 44: left parenthesis, "x" Subscript, 3 , Baseline plus left parenthesis, 2 minus "x" Subscript, 3 , Baseline , right parenthesis "t" , "y" Subscript, 3 , Baseline plus left parenthesis, 3 minus "y" Subscript, 3 , Baseline , right parenthesis "t" , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Uttryck 45: left parenthesis, "x" Subscript, 1 , Baseline plus left parenthesis, 2 minus "x" Subscript, 1 , Baseline , right parenthesis "t" , "y" Subscript, 1 , Baseline plus left parenthesis, 3 minus "y" Subscript, 1 , Baseline , right parenthesis "t" , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Uttryck 46: left parenthesis, "x" Subscript, 2 , Baseline plus left parenthesis, 2 minus "x" Subscript, 2 , Baseline , right parenthesis "t" , "y" Subscript, 2 , Baseline plus left parenthesis, 3 minus "y" Subscript, 2 , Baseline , right parenthesis "t" , right parenthesis

domän t minimum:

less than or equal to "t" less than or equal to

domän t maximum:

Punkter

driven av

left parenthesis, 2 , 3 , right parenthesis

( x₁ ; y₁ ) = ( -6.93 ; -6.93 )

( x₂ ; y₂ ) = ( 5.07 ; 5.07 )

M = ( x₃ ; y₃ ) = ( -0.93 ; -0.93 )