Intersection Finding using Interval Arithmetic

Expression 9: "i" Subscript, "d" "i" "s" "c" "o" "n" "t" "i" "n" "u" "i" "t" "y" "T" "h" "r" "e" "s" "h" "o" "l" "d" , Baseline equals 0.0 0 1

Hidden Label: "i" equals left parenthesis, 1 , 1 , right parenthesis

Label

Expression 11: "x" Subscript, 0 , Baseline equals "f" Subscript, "s" "o" "l" "v" "e" , Baseline left parenthesis, left parenthesis, negative 2 , 5 , right parenthesis , right parenthesis

equals

negative 0.9 1 2 7 1 2 9 3 1 6 3 3

1.3 5 3 4 6 9 6 1 0 2 1

2.5 7 2 2 0 0 7 7 5 1 5

2.9 7 5 7 4 4 7 2 4 2 7

3.2 6 0 0 9 3 6 8 8 9 6

3.5 0 3 2 2 8 4 2 5 9 8

3.7 2 8 6 7 3 3 3 8 8 9

Hidden Label: left parenthesis, "x" Subscript, 0 , Baseline , "f" Subscript, 1 , Baseline left parenthesis, "x" Subscript, 0 , Baseline , right parenthesis , right parenthesis

Label

equals

left parenthesis, negative 0.9 1 2 7 , 2.5 7 9 , right parenthesis

left parenthesis, 1.3 5 3 , 0.5 1 2 9 , right parenthesis

left parenthesis, 2.5 7 2 , 0.2 5 1 , right parenthesis

left parenthesis, 2.9 7 6 , 0.2 9 5 3 , right parenthesis

left parenthesis, 3.2 6 , 0.3 6 5 5 , right parenthesis

left parenthesis, 3.5 0 3 , 0.4 5 1 3 , right parenthesis

left parenthesis, 3.7 2 9 , 0.5 5 1 9 , right parenthesis

Expression 13:

Solving Functions

Interval Arithmetic Functions

Expression 102:

102

Discord: fadaaszhi#1725

103

104