Biểu thức 36: left parenthesis, "h" Subscript, 1 , Baseline , "w" left parenthesis, "h" Subscript, 1 , Baseline , right parenthesis , right parenthesish1,wh1
36
Biểu thức 37: left parenthesis, negative StartFraction, "b" Over 4 "a" , EndFraction , "w" left parenthesis, negative StartFraction, "b" Over 4 "a" , EndFraction , right parenthesis , right parenthesis−b4a,w−b4a
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Biểu thức 38: "p" equals StartFraction, negative 3 "b" squared plus 8 "a" "c" Over 8 "a" squared , EndFractionp=−3b2+8ac8a2
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Biểu thức 39: "q" equals StartFraction, "b" cubed minus 4 "a" "b" "c" plus 8 "a" squared "d" Over 8 "a" cubed , EndFractionq=b3−4abc+8a2d8a3
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Biểu thức 40: "s" equals StartFraction, negative 3 "b" to the 4th power plus 16 "a" "b" squared "c" minus 64 "a" squared "b" "d" plus 256 "a" cubed "f" Over 256 "a" to the 4th power , EndFractions=−3b4+16ab2c−64a2bd+256a3f256a4
40
Biểu thức 41: "i" equals 8i=8
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Biểu thức 42: "j" equals 8 "p"j=8p
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Biểu thức 43: "k" equals 2 "p" squared minus 8 "s"k=2p2−8s
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Biểu thức 44: "l" equals negative "q" squaredl=−q2
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Biểu thức 45: "u" equals StartFraction, negative 2 "j" cubed plus 9 "i" "j" "k" minus 27 "i" squared "l" Over 2 , EndFractionu=−2j3+9ijk−27i2l2
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Biểu thức 46: "v" equals 3 "i" "k" minus "j" squaredv=3ik−j2
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Biểu thức 47: "t" equals StartFraction, negative 8 "p" plus Start Cube Root, "u" plus StartRoot, "u" squared plus "v" cubed , EndRoot , End Cube Root plus Start Cube Root, "u" minus StartRoot, "u" squared plus "v" cubed , EndRoot , End Cube Root Over 3 "i" , EndFraction plus StartFraction, 0 Over "c" squared minus 4 "a" "e" , EndFractiont=−8p+3u+u2+v3+3u−u2+v33i+0c2−4ae
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Biểu thức 48: "z" Subscript, 1 , Baseline equals StartFraction, negative 8 "p" plus 2 StartRoot, negative "v" , EndRoot cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis Over 24 , EndFractionz1=−8p+2−vcoscos−1u−v3324
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Biểu thức 49: "z" Subscript, 2 , Baseline equals StartFraction, negative 8 "p" plus StartRoot, negative "v" , EndRoot left parenthesis, negative cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis minus StartRoot, 3 , EndRoot sin left parenthesis, StartNestedFraction, sin to the negative 1st power left parenthesis, StartRoot, StartNestedFraction, "u" squared plus "v" cubed NestedOver "v" cubed , EndNestedFraction , EndRoot , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis , right parenthesis Over 24 , EndFractionz2=−8p+−v−coscos−1u−v33−3sinsin−1u2+v3v3324
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Biểu thức 50: "z" Subscript, 3 , Baseline equals StartFraction, negative 8 "p" plus StartRoot, negative "v" , EndRoot left parenthesis, negative cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis plus StartRoot, 3 , EndRoot sin left parenthesis, StartNestedFraction, sin to the negative 1st power left parenthesis, StartRoot, StartNestedFraction, "u" squared plus "v" cubed NestedOver "v" cubed , EndNestedFraction , EndRoot , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis , right parenthesis Over 24 , EndFractionz3=−8p+−v−coscos−1u−v33+3sinsin−1u2+v3v3324
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Biểu thức 51: "z" Subscript, 4 , Baseline equals StartFraction, 8 "p" plus 2 StartRoot, negative "v" , EndRoot cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, negative "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis Over 24 , EndFractionz4=8p+2−vcoscos−1−u−v3324
51
Biểu thức 52: "z" Subscript, 5 , Baseline equals StartFraction, 8 "p" plus StartRoot, negative "v" , EndRoot left parenthesis, negative cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, negative "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis minus StartRoot, 3 , EndRoot sin left parenthesis, StartNestedFraction, sin to the negative 1st power left parenthesis, StartRoot, StartNestedFraction, "u" squared plus "v" cubed NestedOver "v" cubed , EndNestedFraction , EndRoot , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis , right parenthesis Over 24 , EndFractionz5=8p+−v−coscos−1−u−v33−3sinsin−1u2+v3v3324
52
Biểu thức 53: "z" Subscript, 6 , Baseline equals StartFraction, 8 "p" plus StartRoot, negative "v" , EndRoot left parenthesis, negative cos left parenthesis, StartNestedFraction, cos to the negative 1st power left parenthesis, StartNestedFraction, negative "u" NestedOver StartRoot, negative "v" cubed , EndRoot , EndNestedFraction , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis plus StartRoot, 3 , EndRoot sin left parenthesis, StartNestedFraction, sin to the negative 1st power left parenthesis, StartRoot, StartNestedFraction, "u" squared plus "v" cubed NestedOver "v" cubed , EndNestedFraction , EndRoot , right parenthesis NestedOver 3 , EndNestedFraction , right parenthesis , right parenthesis Over 24 , EndFractionz6=8p+−v−coscos−1−u−v33+3sinsin−1u2+v3v3324
53
Biểu thức 54: "s" Subscript, 1 , Baseline equals StartFraction, StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot plus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s1=2z1+−2z1+2p+2qz12−b4a+qq−1
54
Biểu thức 55: "s" Subscript, 2 , Baseline equals StartFraction, StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot minus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s2=2z1−−2z1+2p+2qz12−b4a+qq−1
55
Biểu thức 56: "s" Subscript, 3 , Baseline equals StartFraction, StartRoot, 2 "t" , EndRoot plus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s3=2t+−2t+2p+2qt2−b4a+qq−1
56
Biểu thức 57: "s" Subscript, 4 , Baseline equals StartFraction, StartRoot, 2 "t" , EndRoot minus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s4=2t−−2t+2p+2qt2−b4a+qq−1
57
Biểu thức 58: "s" Subscript, 5 , Baseline equals StartFraction, negative StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot plus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s5=−2z1+−2z1+2p−2qz12−b4a+qq−1
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Biểu thức 59: "s" Subscript, 6 , Baseline equals StartFraction, negative StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot minus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s6=−2z1−−2z1+2p−2qz12−b4a+qq−1
59
Biểu thức 60: "s" Subscript, 7 , Baseline equals StartFraction, negative StartRoot, 2 "t" , EndRoot plus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s7=−2t+−2t+2p−2qt2−b4a+qq−1
60
Biểu thức 61: "s" Subscript, 8 , Baseline equals StartFraction, negative StartRoot, 2 "t" , EndRoot minus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartFraction, "q" Over "q" , EndFraction minus 1s8=−2t−−2t+2p−2qt2−b4a+qq−1
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Biểu thức 62: "s" Subscript, 9 , Baseline equals StartRoot, StartFraction, negative "p" plus StartRoot, "p" squared minus 4 "s" , EndRoot Over 2 , EndFraction , EndRoot minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots9=−p+p2−4s2−b4a+−q
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Biểu thức 63: "s" Subscript, 10 , Baseline equals negative StartRoot, StartFraction, negative "p" plus StartRoot, "p" squared minus 4 "s" , EndRoot Over 2 , EndFraction , EndRoot minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots10=−−p+p2−4s2−b4a+−q
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Biểu thức 64: "s" Subscript, 11 , Baseline equals StartFraction, StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot plus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots11=2z1+−2z1+2p+2qz12−b4a+−q
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Biểu thức 65: "s" Subscript, 12 , Baseline equals StartFraction, StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot minus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots12=2z1−−2z1+2p+2qz12−b4a+−q
65
Biểu thức 66: "s" Subscript, 13 , Baseline equals StartFraction, StartRoot, 2 "t" , EndRoot plus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots13=2t+−2t+2p+2qt2−b4a+−q
66
Biểu thức 67: "s" Subscript, 14 , Baseline equals StartFraction, StartRoot, 2 "t" , EndRoot minus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" plus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots14=2t−−2t+2p+2qt2−b4a+−q
67
Biểu thức 68: "s" Subscript, 15 , Baseline equals StartFraction, negative StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot plus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots15=−2z1+−2z1+2p−2qz12−b4a+−q
68
Biểu thức 69: "s" Subscript, 16 , Baseline equals StartFraction, negative StartRoot, 2 "z" Subscript, 1 , Baseline , EndRoot minus StartRoot, negative left parenthesis, 2 "z" Subscript, 1 , Baseline plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "z" Subscript, 1 , Baseline , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots16=−2z1−−2z1+2p−2qz12−b4a+−q
69
Biểu thức 70: "s" Subscript, 17 , Baseline equals StartFraction, negative StartRoot, 2 "t" , EndRoot plus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots17=−2t+−2t+2p−2qt2−b4a+−q
70
Biểu thức 71: "s" Subscript, 18 , Baseline equals StartFraction, negative StartRoot, 2 "t" , EndRoot minus StartRoot, negative left parenthesis, 2 "t" plus 2 "p" minus StartNestedFraction, StartRoot, 2 , EndRoot "q" NestedOver StartRoot, "t" , EndRoot , EndNestedFraction , right parenthesis , EndRoot Over 2 , EndFraction minus StartFraction, "b" Over 4 "a" , EndFraction plus StartRoot, negative StartAbsoluteValue, "q" , EndAbsoluteValue , EndRoots18=−2t−−2t+2p−2qt2−b4a+−q
71
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"a" squareda2
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77
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44
55
66
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| "a" ||a|
,,
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11
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33
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A B C
StartRoot, , EndRoot
piπ
00
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