Look at the parametrically defined function below and compare it to the previous one. Also examine the Table below.
18
Biểu thức 19: left parenthesis, "b" "t" plus 2 , 576 minus 16 left parenthesis, "b" "t" , right parenthesis squared , right parenthesisbt+2,576−16bt2
miền t Cực tiểu: 00
less than or equal to "t" less than or equal to≤t≤
miền t Cực đại: 11
19
"x"x
"y" equals 576 minus 16 left parenthesis, "x" minus 2 , right parenthesis squaredy=576−16x−22
22
r1c2:
r1c3:
33
r2c2:
r2c3:
44
r3c2:
r3c3:
55
r4c2:
r4c3:
66
r5c2:
r5c3:
r6c2:
r6c3:
20
NOW FOR THE STUDENT INVESTIGATION AND QUESTIONS...
21
1. Describe the relationship between the 2 graphs. Be specific.
22
2. Explain the effect of the "+2" in "bt+2" graphically. Why is the domain for the 2nd function 2 <=x<=6?
23
3. Explain algebraically how "576-16(bt)^2" was transformed to 576-16(x-2)^2.
24
4. Fill in the missing coordinates for each graph: Green (___,512); Orange (___,512)
25
5. 'a' and 'b' were both set to 4. What value do we need for 'a' and 'b' in order for the graphs to terminate on the x-axis? Try it! Adjust as needed.
26
7. PLAY the slider for 'a' by pressing the PLAY button to the left. Describe what happens. Now do the same for 'b'. Explain why the curves are repeatedly being traced and 'erased'.
27
28
cung cấp bởi
cung cấp bởi
"x"x
"y"y
"a" squareda2
"a" Superscript, "b" , Baselineab
77
88
99
over÷
chức năng
((
))
less than<
greater than>
44
55
66
times×
| "a" ||a|
,,
less than or equal to≤
greater than or equal to≥
11
22
33
negative−
A B C
StartRoot, , EndRoot
piπ
00
..
equals=
positive+
hoặc
để lưu đồ thị của bạn!
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