運算式 8: "D" Subscript, 0 "A" , Baseline equals StartFraction, "D" Subscript, 1 , Baseline Over 1 minus StartNestedFraction, "d" NestedOver 125 , EndNestedFraction , EndFractionD0A=D11−d125
8
運算式 9: "D" Subscript, 0 "B" , Baseline equals StartFraction, StartRoot, "t" plus 8 , EndRoot StartRoot, left parenthesis, "d" minus 25 , right parenthesis squared left parenthesis, "t" plus 8 , right parenthesis plus 400 "D" Subscript, 1 , Baseline , EndRoot plus left parenthesis, "d" minus 25 , right parenthesis left parenthesis, "t" plus 8 , right parenthesis Over 8 , EndFractionD0B=t+8d−252t+8+400D1+d−25t+88
9
運算式 10: max left parenthesis, "D" Subscript, 0 "A" , Baseline , "D" Subscript, 0 "B" , Baseline , right parenthesismaxD0A,D0B
