Expression 15: 4 "x" Subscript, 0 , Baseline minus 6 equals 04x0−6=0
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Expression 16: "x" Subscript, 0 , Baseline equals 6 quartersx0=64
equals=
1.51.5
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Expression 17: "y" Subscript, 0 , Baseline equals "g" left parenthesis, "x" Subscript, 0 , Baseline , right parenthesisy0=gx0
equals=
55
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Vi bestemmer nu konstanten k
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ved at indsætte røringspunktet
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( x₀ ; y₀ ) = ( x₀ ; g ( x₀ ) )
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i stamfunktionen F ( x ):
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Expression 22: 1 half times 4 times "x" squared minus 6 times "x" Subscript, 0 , Baseline plus "k" equals "y" Subscript, 0 , Baseline12·4·x20−6·x0+k=y0
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Expression 23: "k" equals "y" Subscript, 0 , Baseline minus 1 half times 4 times "x" squared plus 6 times "x" Subscript, 0 , Baselinek=y0−12·4·x20+6·x0
equals=
9.59.5
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Dermed kan stamfunktionen
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skrives på formen:
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Expression 26: "F" left parenthesis, "x" , right parenthesis equals 1 half times 4 "x" squared minus 6 "x" plus 9.5Fx=12·4x2−6x+9.5
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Hjælpelinje og punkter
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left parenthesis, "x" Subscript, 0 , Baseline ; "y" Subscript, 0 , Baseline , right parenthesis equals ( 1.5 ; 5 )x0;y0=(1.5;5)
"f" ( "x" ) equals 4 "x" minus 6f(x)=4x−6
"g" ( "x" ) equals 5g(x)=5
"F" left parenthesis, "x" , right parenthesis equals StartFraction, 4 "x" squared Over 2 , EndFraction minus 6 "x" plus 9.5Fx=4x22−6x+9.5