Hidden Label: left parenthesis, 3 , negative 1 , right parenthesis3,−1
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The radius of the circle is 2. So we need to find all of the points that will have distance of 2 from (3, -1)
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The distance formula between two points is shown below
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Expression 13: StartRoot, left parenthesis, "x" minus "x" Subscript, 1 , Baseline , right parenthesis squared plus left parenthesis, "y" minus "y" Subscript, 1 , Baseline , right parenthesis squared , EndRoot equals "d"x−x12+y−y12=d
add slider:
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If we square both sides, then we have equation for the circle
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Expression 15: left parenthesis, "x" minus "x" Subscript, 1 , Baseline , right parenthesis squared plus left parenthesis, "y" minus "y" Subscript, 1 , Baseline , right parenthesis squared equals 2 squaredx−x12+y−y12=22
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The center point is (3, -1). Move the sliders values there.
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Expression 17: "x" Subscript, 1 , Baseline equals 3x1=3