Convenience function. This tells us which line segment we're on.
7
運算式 8: "f" left parenthesis, theta , right parenthesis equals floor left parenthesis, StartFraction, theta "n" Over 2 pi "j" , EndFraction , right parenthesisfθ=floorθn2πj
8
運算式 9: "r" equals StartFraction, "R" sin left parenthesis, negative StartNestedFraction, 2 pi "j" NestedOver "n" , EndNestedFraction , right parenthesis sec left parenthesis, theta , right parenthesis Over tan left parenthesis, theta , right parenthesis left parenthesis, cos left parenthesis, StartNestedFraction, 2 left parenthesis, "f" left parenthesis, theta , right parenthesis plus 1 , right parenthesis pi "j" NestedOver "n" , EndNestedFraction , right parenthesis minus cos left parenthesis, StartNestedFraction, 2 "f" left parenthesis, theta , right parenthesis pi "j" NestedOver "n" , EndNestedFraction , right parenthesis , right parenthesis minus sin left parenthesis, StartNestedFraction, 2 left parenthesis, "f" left parenthesis, theta , right parenthesis plus 1 , right parenthesis pi "j" NestedOver "n" , EndNestedFraction , right parenthesis plus sin left parenthesis, StartNestedFraction, 2 "f" left parenthesis, theta , right parenthesis pi "j" NestedOver "n" , EndNestedFraction , right parenthesis , EndFractionr=Rsin−2πjnsecθtanθcos2fθ+1πjn−cos2fθπjn−sin2fθ+1πjn+sin2fθπjn
