Biểu thức 8: "V" Subscript, "o" , Baseline left parenthesis, "t" , right parenthesis equals StartFraction, 1 Over "C" , EndFraction "e" Superscript, negative StartFraction, 1 Over "C" "R" , EndFraction "t" , Baseline left parenthesis, StartFraction, 1 Over "R" , EndFraction Start integral from 0 to "t" , end integral, "V" Subscript, "s" , Baseline left parenthesis, "a" , right parenthesis "e" Superscript, StartFraction, 1 Over "C" "R" , EndFraction "a" , Baseline "d" "a" plus "C" Subscript, 1 , Baseline , right parenthesisVot=1Ce−1CRt1R∫t0Vsae1CRada+C1
8
Biểu thức 9: "u" left parenthesis, "t" , right parenthesis equals "V" plus left parenthesis, StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFraction minus "V" , right parenthesis "e" Superscript, negative StartFraction, 1 Over "C" "R" , EndFraction "t" , Baselineut=V+C1C−Ve−1CRt
9
Nhãn ẩn: left parenthesis, StartFraction, "T" Over 2 , EndFraction , "V" plus left parenthesis, StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFraction minus "V" , right parenthesis "e" Superscript, negative StartFraction, 1 Over "C" "R" , EndFraction StartFraction, "T" Over 2 , EndFraction , Baseline , right parenthesisT2,V+C1C−Ve−1CRT2
Nhãn
equals=
left parenthesis, 0.5 5 , 0.8 9 2 4 4 6 6 , right parenthesis0.55,0.8924466
10
Biểu thức 11: "v" left parenthesis, "t" , right parenthesis equals left parenthesis, "e" Superscript, StartFraction, 1 Over "C" "R" , EndFraction StartFraction, "T" Over 2 , EndFraction , Baseline "V" plus left parenthesis, StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFraction minus "V" , right parenthesis , right parenthesis "e" Superscript, negative StartFraction, 1 Over "C" "R" , EndFraction "t" , Baselinevt=e1CRT2V+C1C−Ve−1CRt
11
Nhãn ẩn: left parenthesis, "T" , left parenthesis, "e" Superscript, StartFraction, 1 Over "C" "R" , EndFraction StartFraction, "T" Over 2 , EndFraction , Baseline "V" plus left parenthesis, StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFraction minus "V" , right parenthesis , right parenthesis "e" Superscript, negative StartFraction, 1 Over "C" "R" , EndFraction "T" , Baseline , right parenthesisT,e1CRT2V+C1C−Ve−1CRT
Nhãn
equals=
left parenthesis, 1.1 , 0.0 3 7 5 5 3 4 , right parenthesis1.1,0.0375534
12
Biểu thức 13: "y" equals StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFractiony=C1C
equals=
0.0 3 7 5 5 3 3 9 9 8 1 6 40.0375533998164
13
Biểu thức 14: "y" equals "V" minus StartFraction, "C" Subscript, 1 , Baseline Over "C" , EndFractiony=V−C1C
equals=
0.8 9 2 4 4 6 6 0 0 1 8 40.892446600184
14
15
cung cấp bởi
cung cấp bởi
"x"x
"y"y
"a" squareda2
"a" Superscript, "b" , Baselineab
77
88
99
over÷
chức năng
((
))
less than<
greater than>
44
55
66
times×
| "a" ||a|
,,
less than or equal to≤
greater than or equal to≥
11
22
33
negative−
A B C
StartRoot, , EndRoot
piπ
00
..
equals=
positive+
hoặc
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