นิพจน์ 9: "c" equals rgb left parenthesis, "d" left parenthesis, "c" Subscript, 1 , Baseline left bracket, 1 , right bracket , "c" Subscript, 2 , Baseline left bracket, 1 , right bracket , right parenthesis , "d" left parenthesis, "c" Subscript, 1 , Baseline left bracket, 2 , right bracket , "c" Subscript, 2 , Baseline left bracket, 2 , right bracket , right parenthesis , "d" left parenthesis, "c" Subscript, 1 , Baseline left bracket, 3 , right bracket , "c" Subscript, 2 , Baseline left bracket, 3 , right bracket , right parenthesis , right parenthesisc=rgbdc11,c21,dc12,c22,dc13,c23
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นิพจน์ 10: "d" left parenthesis, "c" Subscript, "o" 1 , Baseline , "c" Subscript, "o" 2 , Baseline , right parenthesis equals StartRoot, "c" squared plus left brace, "p" Subscript, 2 , Baseline . "y" minus "p" Subscript, 1 , Baseline . "y" equals 0 : "p" Subscript, "d" 1 , Baseline left parenthesis, "p" Subscript, 0 , Baseline , right parenthesis , "p" Subscript, "d" , Baseline left parenthesis, "p" Subscript, 0 , Baseline , right parenthesis , right brace left parenthesis, "c" squared minus "c" squared , right parenthesis , EndRootdco1,co2=c2o1+p2.y−p1.y=0:pd1p0,pdp0c2o2−c2o1
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Distance Between Two Lines
ซ่อนโฟลเดอร์นี้จากนักเรียน
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นิพจน์ 12: "f" left parenthesis, "x" , right parenthesis equals "m" left parenthesis, "x" minus "p" Subscript, 1 , Baseline . "x" , right parenthesis plus "p" Subscript, 1 , Baseline . "y"fx=mx−p1.x+p1.y
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นิพจน์ 13: "g" left parenthesis, "x" , right parenthesis equals "m" left parenthesis, "x" minus "p" Subscript, 2 , Baseline . "x" , right parenthesis plus "p" Subscript, 2 , Baseline . "y"gx=mx−p2.x+p2.y
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นิพจน์ 14: "h" Subscript, 1 , Baseline left parenthesis, "x" , "k" , right parenthesis equals "m" left parenthesis, "x" minus "k" . "x" , right parenthesis plus "k" . "y"h1x,k=mx−k.x+k.y
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นิพจน์ 15: "m" equals negative StartFraction, "p" Subscript, 2 , Baseline . "x" minus "p" Subscript, 1 , Baseline . "x" Over "p" Subscript, 2 , Baseline . "y" minus "p" Subscript, 1 , Baseline . "y" , EndFractionm=−p2.x−p1.xp2.y−p1.y
equals=
negative 0.9 6 6 6 1 3 6 7 2 4 9 6−0.966613672496
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นิพจน์ 16: "p" Subscript, "d" , Baseline left parenthesis, "k" , right parenthesis equals StartFraction, "f" left parenthesis, 0 , right parenthesis minus "h" Subscript, 1 , Baseline left parenthesis, 0 , "k" , right parenthesis Over "f" left parenthesis, 0 , right parenthesis minus "g" left parenthesis, 0 , right parenthesis , EndFractionpdk=f0−h10,kf0−g0
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นิพจน์ 17: "p" Subscript, "d" 1 , Baseline left parenthesis, "k" , right parenthesis equals StartFraction, "p" Subscript, 1 , Baseline . "x" minus "k" . "x" Over "p" Subscript, 1 , Baseline . "x" minus "p" Subscript, 2 , Baseline . "x" , EndFractionpd1k=p1.x−k.xp1.x−p2.x
