negative pi
pi
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To get the solution from the original post, set k_R = 1, k_I = 0, c_M = 1, and c_P = -pi/2. To get the alternative real-exponentials solution, set k_R = 0, k_I = -1, c_M = 1, and c_P = 0.
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Any two solutions can be combined by adding them together, or by stitching together their domains, to obtain another solution to f'(x)=f(2x).
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The sum is infinite but N=5 is enough for Desmos's level of precision for most parameter settings.
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0
10
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double check that f'(x) - f(2x):
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