`累乘法` left parenthesis, negative 4 , 3.5 , right parenthesis−4,3.5
Label:
22
"x" Subscript, 4 , Baselinex4
"y" Subscript, 4 , Baseliney4
negative 1−1
11
r1c3:
negative 3−3
33
r2c3:
r3c3:
23
Expression 24: left parenthesis, "x" plus 4 , right parenthesis squared plus left parenthesis, "y" minus 0 , right parenthesis squared equals 2x+42+y−02=2
24
"x" Subscript, 5 , Baselinex5
"y" Subscript, 5 , Baseliney5
negative 2.5 8 6−2.586
00
r1c3:
negative 1.4 1 4−1.414
00
r2c3:
r3c3:
25
`a_{n+1}=\cfrac{2a_n}{2+a_n}` left parenthesis, negative 4 , 0.3 , right parenthesis−4,0.3
Label:
26
`倒数法` left parenthesis, negative 4 , negative 0.5 , right parenthesis−4,−0.5
Label:
27
Expression 28: left parenthesis, "x" plus 4 , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2x+42+y+42=2
28
`a_{n+1}=pa_n+q^n` left parenthesis, negative 4 , negative 3.6 , right parenthesis−4,−3.6
Label:
29
`构造法，同除以q^{n+1}` left parenthesis, negative 4 , negative 4.3 , right parenthesis−4,−4.3
Label:
30
"x" Subscript, 6 , Baselinex6
"y" Subscript, 6 , Baseliney6
negative 1−1
negative 1−1
r1c3:
negative 3−3
negative 3−3
r2c3:
r3c3:
31
Expression 32: left parenthesis, "x" , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2x2+y+42=2
32
`a_n-a_{n+1}=2a_na_{n+1}` left parenthesis, 0 , negative 3.4 , right parenthesis0,−3.4
Label:
33
`同除以a_na_{n+1}` left parenthesis, 0 , negative 3.9 , right parenthesis0,−3.9
Label:
34
"x" Subscript, 7 , Baselinex7
"y" Subscript, 7 , Baseliney7
00
negative 1.4 1 4−1.414
r1c3:
00
negative 2.5 8 6−2.586
r2c3:
r3c3:
35
`S_n-S_{n+1}=3S_nS_{n+1}` left parenthesis, 0 , negative 4.3 , right parenthesis0,−4.3
Label:
36
`思路同上` left parenthesis, 0 , negative 4.8 , right parenthesis0,−4.8
Label:
37
Expression 38: left parenthesis, "x" minus 4 , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2x−42+y+42=2
38
"x" Subscript, 8 , Baselinex8
"y" Subscript, 8 , Baseliney8
11
negative 1−1
r1c3:
33
negative 3−3
r2c3:
r3c3:
39
`周期性` left parenthesis, 3 , negative 4 , right parenthesis3,−4
Label:
40
`a_{n+1}+a_n=k` left parenthesis, 3.3 , negative 3.1 , right parenthesis3.3,−3.1
Label:
41
`a_{n+1}a_n=2^n` left parenthesis, 3.5 , negative 4 , right parenthesis3.5,−4
Label:
42
`a_{n+1}=a_n-a_{n-1}` left parenthesis, 3.2 , negative 4.7 , right parenthesis3.2,−4.7
Label:
43
44
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powered by
"a" Subscript, "n" plus 1 , Baseline minus "a" Subscript, "n" , Baseline equals "m"an+1−an=m
核 心 ， 注 意 内 涵核心，注意内涵
StartFraction, "a" Subscript, "n" plus 1 , Baseline Over "a" Subscript, "n" , Baseline , EndFraction equals "m"an+1an=m
"a" Subscript, "n" plus 1 , Baseline minus "a" Subscript, "n" , Baseline equals "f" ( "n" )an+1−an=f(n)
累 加 法累加法
"a" Subscript, "n" plus 1 , Baseline equals "p" "a" Subscript, "n" , Baseline plus "q"an+1=pan+q
"a" Subscript, "n" plus 1 , Baseline plus "k" equals "p" ( "a" Subscript, "n" , Baseline plus "k" )an+1+k=p(an+k)
构 造 ， "k" equals StartFraction, "q" Over "p" minus 1 , EndFraction构造，k=qp−1
"a" Subscript, "n" , Baseline 与 "S" Subscript, "n" , Baseline 法an与Sn法
"S" Subscript, "n" , Baseline equals "f" ( "n" )Sn=f(n)
"S" Subscript, "n" , Baseline equals "f" ( "a" Subscript, "n" , Baseline )Sn=f(an)
"S" Subscript, "n" , Baseline equals "f" ( "n" ， "a" Subscript, "n" , Baseline )Sn=f(n，an)
StartFraction, "a" Subscript, "n" plus 1 , Baseline Over "a" Subscript, "n" , Baseline , EndFraction equals "f" ( "n" )an+1an=f(n)
累 乘 法累乘法
"a" Subscript, "n" plus 1 , Baseline equals StartFraction, 2 "a" Subscript, "n" , Baseline Over 2 plus "a" Subscript, "n" , Baseline , EndFractionan+1=2an2+an
倒 数 法倒数法
"a" Subscript, "n" plus 1 , Baseline equals "p" "a" Subscript, "n" , Baseline plus "q" Superscript, "n" , Baselinean+1=pan+qn
构 造 法 ， 同 除 以 "q" Superscript, "n" plus 1 , Baseline构造法，同除以qn+1
"a" Subscript, "n" , Baseline minus "a" Subscript, "n" plus 1 , Baseline equals 2 "a" Subscript, "n" , Baseline "a" Subscript, "n" plus 1 , Baselinean−an+1=2anan+1
同 除 以 "a" Subscript, "n" , Baseline "a" Subscript, "n" plus 1 , Baseline同除以anan+1
"S" Subscript, "n" , Baseline minus "S" Subscript, "n" plus 1 , Baseline equals 3 "S" Subscript, "n" , Baseline "S" Subscript, "n" plus 1 , BaselineSn−Sn+1=3SnSn+1
思 路 同 上思路同上
周 期 性周期性
"a" Subscript, "n" plus 1 , Baseline plus "a" Subscript, "n" , Baseline equals "k"an+1+an=k
"a" Subscript, "n" plus 1 , Baseline "a" Subscript, "n" , Baseline equals 2 Superscript, "n" , Baselinean+1an=2n
"a" Subscript, "n" plus 1 , Baseline equals "a" Subscript, "n" , Baseline minus "a" Subscript, "n" minus 1 , Baselinean+1=an−an−1
