数列知识结构图

`累乘法` left parenthesis, negative 4 , 3.5 , right parenthesis

標籤:

"x" Subscript, 4 , Baseline	"y" Subscript, 4 , Baseline
negative 1	1	r1c3:
negative 3	3	r2c3:
		r3c3:

運算式 24: left parenthesis, "x" plus 4 , right parenthesis squared plus left parenthesis, "y" minus 0 , right parenthesis squared equals 2

"x" Subscript, 5 , Baseline	"y" Subscript, 5 , Baseline
negative 2.5 8 6	0	r1c3:
negative 1.4 1 4	0	r2c3:
		r3c3:

`a_{n+1}=\cfrac{2a_n}{2+a_n}` left parenthesis, negative 4 , 0.3 , right parenthesis

標籤:

`倒数法` left parenthesis, negative 4 , negative 0.5 , right parenthesis

標籤:

運算式 28: left parenthesis, "x" plus 4 , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2

`a_{n+1}=pa_n+q^n` left parenthesis, negative 4 , negative 3.6 , right parenthesis

標籤:

`构造法，同除以q^{n+1}` left parenthesis, negative 4 , negative 4.3 , right parenthesis

標籤:

"x" Subscript, 6 , Baseline	"y" Subscript, 6 , Baseline
negative 1	negative 1	r1c3:
negative 3	negative 3	r2c3:
		r3c3:

運算式 32: left parenthesis, "x" , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2

`a_n-a_{n+1}=2a_na_{n+1}` left parenthesis, 0 , negative 3.4 , right parenthesis

標籤:

`同除以a_na_{n+1}` left parenthesis, 0 , negative 3.9 , right parenthesis

標籤:

"x" Subscript, 7 , Baseline	"y" Subscript, 7 , Baseline
0	negative 1.4 1 4	r1c3:
0	negative 2.5 8 6	r2c3:
		r3c3:

`S_n-S_{n+1}=3S_nS_{n+1}` left parenthesis, 0 , negative 4.3 , right parenthesis

標籤:

`思路同上` left parenthesis, 0 , negative 4.8 , right parenthesis

標籤:

運算式 38: left parenthesis, "x" minus 4 , right parenthesis squared plus left parenthesis, "y" plus 4 , right parenthesis squared equals 2

"x" Subscript, 8 , Baseline	"y" Subscript, 8 , Baseline
1	negative 1	r1c3:
3	negative 3	r2c3:
		r3c3:

`周期性` left parenthesis, 3 , negative 4 , right parenthesis

標籤:

`a_{n+1}+a_n=k` left parenthesis, 3.3 , negative 3.1 , right parenthesis

標籤:

`a_{n+1}a_n=2^n` left parenthesis, 3.5 , negative 4 , right parenthesis

標籤:

`a_{n+1}=a_n-a_{n-1}` left parenthesis, 3.2 , negative 4.7 , right parenthesis

標籤:

技術支援

"a" Subscript, "n" plus 1 , Baseline minus "a" Subscript, "n" , Baseline equals "m"

核心，注意内涵

StartFraction, "a" Subscript, "n" plus 1 , Baseline Over "a" Subscript, "n" , Baseline , EndFraction equals "m"

"a" Subscript, "n" plus 1 , Baseline minus "a" Subscript, "n" , Baseline equals "f" ( "n" )

累加法

"a" Subscript, "n" plus 1 , Baseline equals "p" "a" Subscript, "n" , Baseline plus "q"

"a" Subscript, "n" plus 1 , Baseline plus "k" equals "p" ( "a" Subscript, "n" , Baseline plus "k" )

构造， "k" equals StartFraction, "q" Over "p" minus 1 , EndFraction

"a" Subscript, "n" , Baseline 与 "S" Subscript, "n" , Baseline 法

"S" Subscript, "n" , Baseline equals "f" ( "n" )

"S" Subscript, "n" , Baseline equals "f" ( "a" Subscript, "n" , Baseline )

"S" Subscript, "n" , Baseline equals "f" ( "n" ， "a" Subscript, "n" , Baseline )

StartFraction, "a" Subscript, "n" plus 1 , Baseline Over "a" Subscript, "n" , Baseline , EndFraction equals "f" ( "n" )

累乘法

"a" Subscript, "n" plus 1 , Baseline equals StartFraction, 2 "a" Subscript, "n" , Baseline Over 2 plus "a" Subscript, "n" , Baseline , EndFraction

倒数法

"a" Subscript, "n" plus 1 , Baseline equals "p" "a" Subscript, "n" , Baseline plus "q" Superscript, "n" , Baseline

构造法，同除以 "q" Superscript, "n" plus 1 , Baseline

"a" Subscript, "n" , Baseline minus "a" Subscript, "n" plus 1 , Baseline equals 2 "a" Subscript, "n" , Baseline "a" Subscript, "n" plus 1 , Baseline

同除以 "a" Subscript, "n" , Baseline "a" Subscript, "n" plus 1 , Baseline

"S" Subscript, "n" , Baseline minus "S" Subscript, "n" plus 1 , Baseline equals 3 "S" Subscript, "n" , Baseline "S" Subscript, "n" plus 1 , Baseline

思路同上

周期性

"a" Subscript, "n" plus 1 , Baseline plus "a" Subscript, "n" , Baseline equals "k"

"a" Subscript, "n" plus 1 , Baseline "a" Subscript, "n" , Baseline equals 2 Superscript, "n" , Baseline

"a" Subscript, "n" plus 1 , Baseline equals "a" Subscript, "n" , Baseline minus "a" Subscript, "n" minus 1 , Baseline