It's all fun and games till someone shoots their i out. This turns out to be the best one: the square root is taken to be in -pi/2 to 3pi/2 instead of -pi to pi. This is done by hacking the 2-argument arctangent to first rotate the points clockwise by 90° and then adding the 90° back directly. This corresponds to taking branch cut along the imaginary axis from -infinity to -i, and -infinity to -i. We will see that the overlapping part *cancels out*, meaning that this amounts to a cut along the segment i[-1,1].