นิพจน์ 12: "y" equals "y" Subscript, 0 , Baseline left brace, "x" Subscript, 0 , Baseline less than "x" less than "x" Subscript, 0 , Baseline plus "a" , right bracey=y0x0<x<x0+a
12
นิพจน์ 13: "x" equals "x" Subscript, 0 , Baseline plus "a" left brace, "y" Subscript, 0 , Baseline less than "y" less than "y" Subscript, 0 , Baseline plus "b" , right brace left brace, "b" greater than 0 , right bracex=x0+ay0<y<y0+bb>0
13
${a} left parenthesis, StartFraction, "x" Subscript, 0 , Baseline plus "x" Subscript, 0 , Baseline plus "a" Over 2 , EndFraction , "y" Subscript, 0 , Baseline minus 1.1 left brace, "b" greater than 0 , right brace , right parenthesisx0+x0+a2,y0−1.1b>0
ป้ายกำกับ:
equals=
left parenthesis, negative 4.5 , negative 1.1 , right parenthesis−4.5,−1.1
14
${b} left parenthesis, "x" Subscript, 0 , Baseline plus "a" plus 1 , StartFraction, "y" Subscript, 0 , Baseline plus "y" Subscript, 0 , Baseline plus "b" Over 2 , EndFraction , right parenthesisx0+a+1,y0+y0+b2
ป้ายกำกับ:
equals=
left parenthesis, negative 1 , 5 , right parenthesis−1,5
15
นิพจน์ 16: "x" equals "x" Subscript, 0 , Baseline plus "a" left brace, "y" Subscript, 0 , Baseline greater than "y" greater than "y" Subscript, 0 , Baseline plus "b" , right brace left brace, "b" less than 0 , right bracex=x0+ay0>y>y0+bb<0
ยังไม่ได้กำหนด
16
นิพจน์ 17: "y" minus "y" Subscript, 0 , Baseline equals StartFraction, "b" Over "a" , EndFraction left parenthesis, "x" minus "x" Subscript, 0 , Baseline , right parenthesisy−y0=bax−x0
17
${a} left parenthesis, StartFraction, "x" Subscript, 0 , Baseline plus "x" Subscript, 0 , Baseline plus "a" Over 2 , EndFraction , "y" Subscript, 0 , Baseline plus 1.1 left brace, "b" less than 0 , right brace , right parenthesisx0+x0+a2,y0+1.1b<0
ป้ายกำกับ:
ยังไม่ได้กำหนด
18
ซ่อน CORRECT! left parenthesis, 4 , 1 left brace, StartFraction, "b" Over "a" , EndFraction equals negative 5 halves , right brace , right parenthesis4,1ba=−52
ป้ายกำกับ:
ยังไม่ได้กำหนด
19
นิพจน์ 20: "L" Subscript, 1 , Baseline equals left bracket, "x" Subscript, 0 , Baseline plus 1 , ... , "x" Subscript, 0 , Baseline plus "a" , right bracketL1=x0+1,...,x0+a
equals=
negative 6−6
negative 5−5
negative 4−4
negative 3−3
negative 2−2
20
นิพจน์ 21: "x" equals "L" Subscript, 1 , Baseline left brace, "y" Subscript, 0 , Baseline minus 0.3 less than "y" less than "y" Subscript, 0 , Baseline plus 0.3 , right bracex=L1y0−0.3<y<y0+0.3
21
นิพจน์ 22: "L" Subscript, 2 , Baseline equals left bracket, "y" Subscript, 0 , Baseline , ... , "y" Subscript, 0 , Baseline plus "b" , right bracketL2=y0,...,y0+b
equals=
00
11
22
33
44
55
66
77
88
99
1010
22
นิพจน์ 23: "y" equals "L" Subscript, 2 , Baseline left brace, "x" Subscript, 0 , Baseline plus "a" minus 0.3 less than "x" less than "x" Subscript, 0 , Baseline plus "a" plus 0.3 , right bracey=L2x0+a−0.3<x<x0+a+0.3
