運算式 14: left bracket, negative StartFraction, 1 Over "u" , EndFraction "d" "u" , right bracket equals negative natural log "u" plus "c"−1udu=−lnu+c
14
Dermed er stamfunktionen
15
運算式 16: "F" left parenthesis, "x" , right parenthesis equals negative natural log left parenthesis, 4 minus "x" , right parenthesis plus "c"Fx=−ln4−x+c
16
運算式 17: Start integral from "i" to "x" , end integral, StartFraction, 1 Over 4 minus "t" , EndFraction "d" "t" plus "c"∫xi14−tdt+c
