表达式46: theta Subscript, 1 , Baseline equals tangent to the negative 1st power StartFraction, "E" Subscript, 2 , Baseline Over "E" Subscript, 1 , Baseline , EndFraction plus 135θ1=tan−1E2E1+135
46
Graphs
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47
表达式48: "y" less than 25y<25
48
表达式49: polygon left parenthesis, "A" , "E" , "M" , "E" , "A" , "B" , "C" , "M" , "F" , "C" , "D" , right parenthesispolygonA,E,M,E,A,B,C,M,F,C,D
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表达式50: left parenthesis, "L" Subscript, 1 , Baseline plus StartFraction, 0.7 5 "t" cos left parenthesis, theta Subscript, 1 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "L" Subscript, 2 , Baseline plus StartFraction, 0.7 5 "t" sin left parenthesis, theta Subscript, 1 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisL1+0.75tcosθ1+1352,L2+0.75tsinθ1+1352
50
表达式51: left parenthesis, "L" Subscript, 1 , Baseline plus StartFraction, 0.7 5 "t" cos left parenthesis, theta Subscript, 1 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "L" Subscript, 2 , Baseline plus StartFraction, 0.7 5 "t" sin left parenthesis, theta Subscript, 1 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisL1+0.75tcosθ1−1352,L2+0.75tsinθ1−1352
51
表达式52: left parenthesis, "K" Subscript, 1 , Baseline plus StartFraction, 0.7 5 "t" cos left parenthesis, theta Subscript, 2 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "K" Subscript, 2 , Baseline plus StartFraction, 0.7 5 "t" sin left parenthesis, theta Subscript, 2 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisK1+0.75tcosθ2+1352,K2+0.75tsinθ2+1352
52
表达式53: left parenthesis, "K" Subscript, 1 , Baseline plus StartFraction, 0.7 5 "t" cos left parenthesis, theta Subscript, 2 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "K" Subscript, 2 , Baseline plus StartFraction, 0.7 5 "t" sin left parenthesis, theta Subscript, 2 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisK1+0.75tcosθ2−1352,K2+0.75tsinθ2−1352