式6: "D" equals left parenthesis, 1.7 5 , negative 0.6 6 , right parenthesisD=1.75,−0.66
6
式7: "T" equals 0.4T=0.4
7
solve points on the quadric f(P)=1
8
式9: "f" left parenthesis, "P" , right parenthesis equals "a" "P" . "x" squared plus "b" "P" . "y" squared plus "c" "P" . "x" "P" . "y" plus "d" "P" . "x" plus "e" Subscript, 0 , Baseline "P" . "y" plus "f" Subscript, 0 , BaselinefP=aP.x2+bP.y2+cP.xP.y+dP.x+e0P.y+f0
9
式10: left parenthesis, "f" left parenthesis, "A" , right parenthesis minus 1 , right parenthesis squared plus left parenthesis, "f" left parenthesis, "B" , right parenthesis minus 1 , right parenthesis squared plus left parenthesis, "f" left parenthesis, "C" , right parenthesis minus 1 , right parenthesis squared plus left parenthesis, "f" left parenthesis, "D" , right parenthesis minus 1 , right parenthesis squared tilde 0fA−12+fB−12+fC−12+fD−12~0
10
trace quadric
11
式12: "f" left parenthesis, left parenthesis, "x" , "y" , right parenthesis , right parenthesis equals 1fx,y=1