Why does this value for k work? Explain what you see geometrically, and if possible explain algebraically. Answer: This value for k works, as when k=2, the graph becomes a straight line, and so the limit of the function should exist at every point. Algebraically, k=2 would work because when the numerator is factorized, it would equal to (x-2)(x+1), and so the (x-2) would cancel out, leaving the function for a straight line, where a limit would exist for all functions.