Expression 26: "b" equals "r" left parenthesis, 36000 times "L" plus 10800 times "W" , right parenthesis plus 1800 times "R"b=r36000·L+10800·W+1800·R
equals=
119880119880
26
train mass (kg)
27
Expression 28: "m" equals 2000 "L" plus 1000 "W"m=2000L+1000W
equals=
60006000
28
Number of Trains (integer) deprecated, replaced by variable to graph, left here to explain other formulas
29
Expression 30: "N" equals 2N=2
11
5050
30
Unoccupied Space (tile)
31
Expression 32: "s" equals "o" minus "N" times "T"s=o−N·T
equals=
798.3 9 3 5 0 4 0 5798.39350405
32
Space Available for braking per train (tile)
33
Expression 34: "A" equals StartFraction, "s" Over "N" , EndFractionA=sN
equals=
399.1 9 6 7 5 2 0 2 5399.196752025
34
Max corresponding Speed (km/h)
35
Expression 36: "v" equals StartFraction, left parenthesis, StartRoot, 2 "b" , EndRoot times StartRoot, "A" , EndRoot , right parenthesis Over StartRoot, "m" , EndRoot , EndFraction times 3.6v=2b·Am·3.6
equals=
454.6 8 3 0 2 4 3 7 4454.683024374
36
Max corresponding Speed for this number of trains on the loop (km/h)
37
Expression 38: "G" left parenthesis, "y" , right parenthesis equals min left parenthesis, StartFraction, left parenthesis, StartRoot, 2 "b" , EndRoot times StartRoot, StartNestedFraction, "o" minus "K" left parenthesis, "y" , right parenthesis times "T" NestedOver "K" left parenthesis, "y" , right parenthesis , EndNestedFraction , EndRoot , right parenthesis Over StartRoot, "m" , EndRoot , EndFraction times 3.6 , "j" , right parenthesisGy=min2b·o−Ky·TKym·3.6,j
38
I tried K(y)=round(y) but it should be truncation i don't know how to
39
Expression 40: "K" left parenthesis, "y" , right parenthesis equals left parenthesis, "y" , right parenthesisKy=y
40
Theoric train max speed
41
Expression 42: "j" equals min left parenthesis, "p" , "g" times 3.6 , right parenthesisj=minp,g·3.6
equals=
298.0 8298.08
42
Forward force (acceleration - friction) /drag ( Newton)
43
Expression 44: "g" equals StartFraction, max left parenthesis, "a" left parenthesis, 36000 "L" , right parenthesis minus 1800 times "R" , 0 , right parenthesis Over 450 , EndFractiong=maxa36000L−1800·R,0450
equals=
180180
44
Game max speed given fuel (km/h)
45
Expression 46: "p" equals 1.2 times 60 times 3.6 times "f"p=1.2·60·3.6·f
equals=
298.0 8298.08
46
Throughput ( train per minute given number of train on the loop )
47
Expression 48: "D" left parenthesis, "y" , right parenthesis equals StartFraction, left parenthesis, StartNestedFraction, left parenthesis, StartRoot, 2 "b" , EndRoot times StartRoot, StartNestedFraction, "o" minus "y" times "T" NestedOver "y" , EndNestedFraction , EndRoot , right parenthesis NestedOver StartRoot, "m" , EndRoot , EndNestedFraction times 3.6 , right parenthesis Over StartNestedFraction, "o" NestedOver 1000 , EndNestedFraction , EndFraction times "y" times StartFraction, 1 Over 60 , EndFractionDy=2b·o−y·Tym·3.6o1000·y·160
48
Max throughput for this type of train is the maximum of the previous function