นิพจน์ 7: "B" Subscript, "x" , Baseline left parenthesis, "t" , right parenthesis equals "P" Subscript, 0 , Baseline . "x" plus "t" left parenthesis, negative 3 "P" Subscript, 0 , Baseline . "x" plus 3 "P" Subscript, 1 , Baseline . "x" , right parenthesis plus "t" squared left parenthesis, 3 "P" Subscript, 0 , Baseline . "x" minus 6 "P" Subscript, 1 , Baseline . "x" plus 3 "P" Subscript, 2 , Baseline . "x" , right parenthesis plus "t" cubed left parenthesis, negative "P" Subscript, 0 , Baseline . "x" plus 3 "P" Subscript, 1 , Baseline . "x" minus 3 "P" Subscript, 2 , Baseline . "x" plus "P" Subscript, 3 , Baseline . "x" , right parenthesisBxt=P0.x+t−3P0.x+3P1.x+t23P0.x−6P1.x+3P2.x+t3−P0.x+3P1.x−3P2.x+P3.x
7
นิพจน์ 8: "B" Subscript, "y" , Baseline left parenthesis, "t" , right parenthesis equals "P" Subscript, 0 , Baseline . "y" plus "t" left parenthesis, negative 3 "P" Subscript, 0 , Baseline . "y" plus 3 "P" Subscript, 1 , Baseline . "y" , right parenthesis plus "t" squared left parenthesis, 3 "P" Subscript, 0 , Baseline . "y" minus 6 "P" Subscript, 1 , Baseline . "y" plus 3 "P" Subscript, 2 , Baseline . "y" , right parenthesis plus "t" cubed left parenthesis, negative "P" Subscript, 0 , Baseline . "y" plus 3 "P" Subscript, 1 , Baseline . "y" minus 3 "P" Subscript, 2 , Baseline . "y" plus "P" Subscript, 3 , Baseline . "y" , right parenthesisByt=P0.y+t−3P0.y+3P1.y+t23P0.y−6P1.y+3P2.y+t3−P0.y+3P1.y−3P2.y+P3.y
8
connections
ซ่อนโฟลเดอร์นี้จากนักเรียน
9
connections 2
ซ่อนโฟลเดอร์นี้จากนักเรียน
13
connections 3
ซ่อนโฟลเดอร์นี้จากนักเรียน
18
นิพจน์ 20: left parenthesis, "B" Subscript, "x" , Baseline left parenthesis, "t" , right parenthesis , "B" Subscript, "y" , Baseline left parenthesis, "t" , right parenthesis , right parenthesisBxt,Byt