Wyrażenie 25: "n" Subscript, "x" , Baseline left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisnxsn1
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Wyrażenie 26: "n" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis equals floor left parenthesis, StartFraction, "x" minus "a" Over "d" Subscript, "x" , Baseline , EndFraction , right parenthesisnxx=floorx−adx
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Wyrażenie 27: 0 less than or equal to "y" less than or equal to "f" left parenthesis, "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis "D" to the 0 power0≤y≤fsxxD0
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Wyrażenie 28: 0 greater than or equal to "y" greater than or equal to "f" left parenthesis, "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis "D" to the 0 power0≥y≥fsxxD0
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Wyrażenie 29: "f" left parenthesis, "x" , right parenthesisfx
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Wyrażenie 30: "F" left parenthesis, "x" , right parenthesisFx
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Wyrażenie 31: "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis equals left brace, "a" less than or equal to "x" less than or equal to "b" : "s" left parenthesis, "n" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis , right bracesxx=a≤x≤b:snxx
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rektanglernes højder og numre
Ukryj ten folder przed uczniami.
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Hvis for eksempel:
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Wyrażenie 34: "n" Subscript, 1 , Baseline equals 298n1=298
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så er funktionen:
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Wyrażenie 36: "f" left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisfsn1
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= højden af rektangel nummer:
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Wyrażenie 38: "n" Subscript, 1 , Baselinen1
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da første rektangelnummer er 0.
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Stiplet vandret linje:
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Wyrażenie 41: "y" equals "f" left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisy=fsn1
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Rektangelnummerets x-værdi:
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Wyrażenie 43: "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesissn1
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Stiplet lodret linje:
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Wyrażenie 45: "x" equals "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesisx=sn1
