運算式 25: "n" Subscript, "x" , Baseline left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisnxsn1
25
運算式 26: "n" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis equals floor left parenthesis, StartFraction, "x" minus "a" Over "d" Subscript, "x" , Baseline , EndFraction , right parenthesisnxx=floorx−adx
26
運算式 27: 0 less than or equal to "y" less than or equal to "f" left parenthesis, "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis "D" to the 0 power0≤y≤fsxxD0
27
運算式 28: 0 greater than or equal to "y" greater than or equal to "f" left parenthesis, "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis "D" to the 0 power0≥y≥fsxxD0
28
運算式 29: "f" left parenthesis, "x" , right parenthesisfx
29
運算式 30: "F" left parenthesis, "x" , right parenthesisFx
30
運算式 31: "s" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis equals left brace, "a" less than or equal to "x" less than or equal to "b" : "s" left parenthesis, "n" Subscript, "x" , Baseline left parenthesis, "x" , right parenthesis , right parenthesis , right bracesxx=a≤x≤b:snxx
31
rektanglernes højder og numre
對學生隱藏此資料夾。
32
Hvis for eksempel:
33
運算式 34: "n" Subscript, 1 , Baseline equals 298n1=298
34
så er funktionen:
35
運算式 36: "f" left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisfsn1
36
= højden af rektangel nummer:
37
運算式 38: "n" Subscript, 1 , Baselinen1
38
da første rektangelnummer er 0.
39
Stiplet vandret linje:
40
運算式 41: "y" equals "f" left parenthesis, "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesis , right parenthesisy=fsn1
41
Rektangelnummerets x-værdi:
42
運算式 43: "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesissn1
43
Stiplet lodret linje:
44
運算式 45: "x" equals "s" left parenthesis, "n" Subscript, 1 , Baseline , right parenthesisx=sn1
