นิพจน์ 631: "P" Subscript, "r" "e" "d" "i" "c" "t" "i" "o" "n" , Baseline equals left bracket, 0...9 , right bracket left bracket, "a" Subscript, 3 , Baseline equals max left parenthesis, "a" Subscript, 3 , Baseline , right parenthesis , right bracket left bracket, 1 , right bracketPrediction=0...9a3=maxa31
631
นิพจน์ 632: "R" Subscript, "e" "s" "e" "t" , Baseline equals "X" Subscript, "p" "o" "s" , Baseline to left bracket, "P" . "x" , right bracket , "Y" Subscript, "p" "o" "s" , Baseline to left bracket, "P" . "y" , right bracketReset=Xpos→P.x,Ypos→P.y
632
นิพจน์ 633: "P" Subscript, "e" "r" "c" "e" "n" "t" "a" "g" "e" , Baseline equals 0.2 9 5Percentage=0.295
633
นิพจน์ 634: "a" Subscript, 3 , Baseline left bracket, "x" minus "x" Subscript, "m" "a" "x" , Baseline , right bracket minus 0.2a3x−xmax−0.2
634
NN visualization
ซ่อนโฟลเดอร์นี้จากนักเรียน
635
นิพจน์ 649: "F" plus left parenthesis, 2 , 1 , right parenthesisF+2,1
