นิพจน์ 23: theta Subscript, 1 , Baseline equals tangent to the negative 1st power StartFraction, "D" Subscript, 2 , Baseline Over "D" Subscript, 1 , Baseline , EndFraction minus 135θ1=tan−1D2D1−135
23
Graphs
ซ่อนโฟลเดอร์นี้จากนักเรียน
24
นิพจน์ 25: "y" less than 25y<25
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นิพจน์ 26: polygon left parenthesis, "A" , "C" , "D" , right parenthesispolygonA,C,D
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นิพจน์ 27: left parenthesis, "E" Subscript, 1 , Baseline plus 0.5cos 45 , 0.5 "t" sin 45 , right parenthesisE1+0.5cos45,0.5tsin45
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นิพจน์ 28: left parenthesis, "E" Subscript, 1 , Baseline plus 0.5 "t" cos 45 , 0.5sin 45 , right parenthesisE1+0.5tcos45,0.5sin45
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นิพจน์ 29: polygon left parenthesis, "A" , "C" , "A" , "E" , "D" , "E" , "B" , "C" , "D" , right parenthesispolygonA,C,A,E,D,E,B,C,D
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นิพจน์ 30: left parenthesis, "B" Subscript, 1 , Baseline plus 0.5cos 135 , 0.5 "t" sin 45 , right parenthesisB1+0.5cos135,0.5tsin45
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นิพจน์ 31: left parenthesis, "B" Subscript, 1 , Baseline plus 0.5 "t" cos 135 , 0.5sin 45 , right parenthesisB1+0.5tcos135,0.5sin45
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นิพจน์ 32: left parenthesis, "K" Subscript, 1 , Baseline plus StartFraction, 0.5 "t" cos left parenthesis, theta Subscript, 1 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "K" Subscript, 2 , Baseline plus StartFraction, 0.5 "t" sin left parenthesis, theta Subscript, 1 , Baseline minus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisK1+0.5tcosθ1−1352,K2+0.5tsinθ1−1352
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นิพจน์ 33: left parenthesis, "K" Subscript, 1 , Baseline plus StartFraction, 0.5 "t" cos left parenthesis, theta Subscript, 1 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , "K" Subscript, 2 , Baseline plus StartFraction, 0.5 "t" sin left parenthesis, theta Subscript, 1 , Baseline plus 135 , right parenthesis Over StartRoot, 2 , EndRoot , EndFraction , right parenthesisK1+0.5tcosθ1+1352,K2+0.5tsinθ1+1352