Pick an amount for d_x, it has to be really small!
14
運算式 15: "d" Subscript, "x" , Baseline equals 0dx=0
00
0.10.1
15
Now below, divide the value of dy (shown on the graph) with the value of dx! That value is close to something...(You can also call on the value of dy by typing d_y)
16
運算式 17: StartFraction, "d" Subscript, "y" , Baseline Over "d" Subscript, "x" , Baseline , EndFractiondydx
無法辨識
17
運算式 18:
18
運算式 19: "y" equals "f" left parenthesis, "c" , right parenthesis left brace, "c" less than or equal to "x" less than or equal to "c" plus "d" Subscript, "x" , Baseline , right brace left brace, "v" equals 1 , right bracey=fcc≤x≤c+dxv=1
無法辨識
19
運算式 20: "x" equals "c" plus "d" Subscript, "x" , Baseline left brace, "f" left parenthesis, "c" , right parenthesis less than or equal to "y" less than or equal to "f" left parenthesis, "c" plus "d" Subscript, "x" , Baseline , right parenthesis , right brace left brace, "v" equals 1 , right bracex=c+dxfc≤y≤fc+dxv=1
無法辨識
20
運算式 21: "x" equals "c" plus "d" Subscript, "x" , Baseline left brace, "f" left parenthesis, "c" plus "d" Subscript, "x" , Baseline , right parenthesis less than or equal to "y" less than or equal to "f" left parenthesis, "c" , right parenthesis , right brace left brace, "v" equals 1 , right bracex=c+dxfc+dx≤y≤fcv=1
無法辨識
21
運算式 22: "f" left parenthesis, "x" , right parenthesis equals StartFraction, "x" cubed Over 2 , EndFraction minus "x" cosine "x" minus 2 "x" squared plus "x" sine left parenthesis, "x" squared , right parenthesisfx=x32−xcosx−2x2+xsinx2
22
dx = ${d_x} left parenthesis, "c" plus StartFraction, "d" Subscript, "x" , Baseline Over 2 , EndFraction , "f" left parenthesis, "c" , right parenthesis plus 0.0 0 2 , right parenthesis left brace, "v" equals 1 , right brace left brace, "d" Subscript, "x" , Baseline greater than 0 , right bracec+dx2,fc+0.002v=1dx>0
標籤:
無法辨識
23
運算式 24: "q" equals "f" left parenthesis, "c" plus "d" Subscript, "x" , Baseline , right parenthesis minus "f" left parenthesis, "c" , right parenthesisq=fc+dx−fc
equals=
00
24
dy = ${q} left parenthesis, "c" plus "d" Subscript, "x" , Baseline , left parenthesis, StartFraction, "f" left parenthesis, "c" , right parenthesis plus "f" left parenthesis, "c" plus "d" Subscript, "x" , Baseline , right parenthesis Over 2 , EndFraction , right parenthesis , right parenthesis left brace, "v" equals 1 , right brace left brace, "d" Subscript, "x" , Baseline greater than 0 , right bracec+dx,fc+fc+dx2v=1dx>0
