This function looked like a mountain so I plopped a lil sun in da middle :D.
運算式 6: StartFraction, left bracket, "M" ...1 , right bracket Over "M" , EndFraction "h" left parenthesis, left bracket, "M" ...1 , right bracket , 2 "t" plus 1 half , right parenthesis "g" left parenthesis, "t" , right parenthesisM...1MhM...1,2t+12gt
00
定義域 t 最小值：
less than or equal to "t" less than or equal to≤t≤
11
定義域 t 最大值：
6
運算式 7: "C" equals hsv left parenthesis, StartFraction, left bracket, 0... "M" minus 1 , right bracket Over "M" , EndFraction 1 sixth 360 , 1 , 1 , right parenthesisC=hsv0...M−1M16360,1,1
7
運算式 8: "M" equals 15M=15
11
2 to the 6th power26
8
運算式 9: left bracket, negative "f" left parenthesis, "t" , right parenthesis , "f" left parenthesis, "t" , right parenthesis , left parenthesis, negative "f" left parenthesis, "t" , right parenthesis . "x" , "f" left parenthesis, "t" , right parenthesis . "y" , right parenthesis , left parenthesis, "f" left parenthesis, "t" , right parenthesis . "x" , negative "f" left parenthesis, "t" , right parenthesis . "y" , right parenthesis , right bracket−ft,ft,−ft.x,ft.y,ft.x,−ft.y
00
定義域 t 最小值：
less than or equal to "t" less than or equal to≤t≤
定義域 t 最大值： 11
9
運算式 10: left parenthesis, pi left parenthesis, mod left parenthesis, floor left parenthesis, "T" , right parenthesis , 2 , right parenthesis , right parenthesis plus left parenthesis, 1 minus 2mod left parenthesis, floor left parenthesis, "T" , right parenthesis , 2 , right parenthesis , right parenthesis "f" left parenthesis, mod left parenthesis, "T" , 1 , right parenthesis , right parenthesis . "x" , "f" left parenthesis, mod left parenthesis, "T" , 1 , right parenthesis , right parenthesis . "y" , right parenthesis plus left parenthesis, pi floor left parenthesis, "T" , right parenthesis , 0 , right parenthesis with "T" equals StartFraction, "t" Over StartRoot, 1 minus "t" squared , EndRoot , EndFractionπmodfloorT,2+1−2modfloorT,2fmodT,1.x,fmodT,1.y+πfloorT,0withT=t1−t2
00
定義域 t 最小值：
less than or equal to "t" less than or equal to≤t≤
定義域 t 最大值： 11
10
運算式 11: "x" squared plus left parenthesis, "y" minus 1.5 , right parenthesis squared equals 2 left brace, "y" greater than or equal to 1.6 5 1 , right bracex2+y−1.52=2y≥1.651
