表达式12: "o" Subscript, "x" , Baseline equals "o" cosine left parenthesis, StartFraction, pi Over 2 , EndFraction plus pi plus phi , right parenthesisox=ocosπ2+π+ϕ
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表达式13: "o" Subscript, "y" , Baseline equals "o" sine left parenthesis, StartFraction, pi Over 2 , EndFraction plus pi plus phi , right parenthesisoy=osinπ2+π+ϕ
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表达式14: "i" Subscript, 1 , Baseline equals "i" cosine left parenthesis, 0 plus phi , right parenthesisi1=icos0+ϕ
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表达式15: "i" Subscript, 2 , Baseline equals "i" sine left parenthesis, 0 plus phi , right parenthesisi2=isin0+ϕ
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表达式16: "i" Subscript, "x" , Baseline equals "i" cosine left parenthesis, 0 plus pi plus phi , right parenthesisix=icos0+π+ϕ
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表达式17: "i" Subscript, "y" , Baseline equals "i" sine left parenthesis, 0 plus pi plus phi , right parenthesisiy=isin0+π+ϕ
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Line Segments
对学生隐藏该文件夹。
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表达式19: left parenthesis, "o" Subscript, 1 , Baseline plus left parenthesis, "i" Subscript, 1 , Baseline minus "o" Subscript, 1 , Baseline , right parenthesis "t" , "o" Subscript, 2 , Baseline plus left parenthesis, "i" Subscript, 2 , Baseline minus "o" Subscript, 2 , Baseline , right parenthesis "t" , right parenthesiso1+i1−o1t,o2+i2−o2t
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表达式20: left parenthesis, "o" Subscript, 1 , Baseline minus left parenthesis, "i" Subscript, 1 , Baseline plus "o" Subscript, 1 , Baseline , right parenthesis "t" , "o" Subscript, 2 , Baseline plus left parenthesis, "i" Subscript, 2 , Baseline minus "o" Subscript, 2 , Baseline , right parenthesis "t" , right parenthesiso1−i1+o1t,o2+i2−o2t
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表达式21: left parenthesis, "o" Subscript, "x" , Baseline plus left parenthesis, "i" Subscript, "x" , Baseline minus "o" Subscript, "x" , Baseline , right parenthesis "t" , "o" Subscript, "y" , Baseline plus left parenthesis, "i" Subscript, "y" , Baseline minus "o" Subscript, "y" , Baseline , right parenthesis "t" , right parenthesisox+ix−oxt,oy+iy−oyt
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表达式22: left parenthesis, "o" Subscript, "x" , Baseline minus left parenthesis, "i" Subscript, "x" , Baseline plus "o" Subscript, "x" , Baseline , right parenthesis "t" , "o" Subscript, "y" , Baseline plus left parenthesis, "i" Subscript, "y" , Baseline minus "o" Subscript, "y" , Baseline , right parenthesis "t" , right parenthesisox−ix+oxt,oy+iy−oyt