A hare is chased by a dog and is 57 jumps ahead of it. Each time the hare makes 3 jumps, the dog only makes 2 jumps, each of which is twice as long as those of the hare. - How many jumps (including those 57) has the hare made before it is caught by the dog? Hint: 57 + 3 · 57
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Solution
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Hver gang haren foretager 3 spring, reduceres afstanden mellem den og hunden med 1 harespring. 57 + 3 · 57 = 228 spring.
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Each time the hare makes 3 jumps, the distance between it and the dog is reduced by 1 one hare jump. 57 + 3 · 57 = 228 jumps.
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