運算式 18: left parenthesis, "x" Subscript, 0 , Baseline plus "a" plus left parenthesis, "P" Subscript, 1 , Baseline minus "x" Subscript, 0 , Baseline minus "a" , right parenthesis "t" , "y" Subscript, 0 , Baseline plus left parenthesis, "P" Subscript, 2 , Baseline minus "y" Subscript, 0 , Baseline , right parenthesis "t" , right parenthesisx0+a+P1−x0−at,y0+P2−y0t
00
定義域 t 最小值：
less than or equal to "t" less than or equal to≤t≤
11
定義域 t 最大值：
18
運算式 19: "y" equals "C" Subscript, "y" , Baseline left brace, "C" Subscript, "y" , Baseline greater than 0 , "C" Subscript, "y" , Baseline less than 0 , right bracey=CyCy>0,Cy<0
equals=
negative 1−1
19
運算式 20: left parenthesis, "x" Subscript, 0 , Baseline plus "a" plus left parenthesis, negative "a" , right parenthesis "t" , "y" Subscript, 0 , Baseline times left bracket, 1 , 1 , 1 , right bracket , right parenthesisx0+a+−at,y0·1,1,1
00
定義域 t 最小值：
less than or equal to "t" less than or equal to≤t≤
11
定義域 t 最大值：
20
Tangentens ligning
對學生隱藏此資料夾。
21
( P₁ ; P₂ ) = Røringspunktets
22
koordinater trækkes fra
23
cirkelcentrets koordinater:
24
運算式 25: "a" Subscript, "t" , Baseline equals "x" Subscript, 0 , Baseline minus "P" Subscript, 1 , Baselineat=x0−P1
運算式 32: "a" Subscript, "t" , Baseline left parenthesis, "x" minus "P" Subscript, 1 , Baseline , right parenthesis plus "b" Subscript, "t" , Baseline left parenthesis, "y" minus "P" Subscript, 2 , Baseline , right parenthesis equals 0atx−P1+bty−P2=0
32
運算式 33: "y" equals negative StartFraction, "a" Over "b" , EndFraction times "x" plus StartFraction, "a" times "P" Subscript, 1 , Baseline Over "b" , EndFraction plus StartFraction, "b" times "P" Subscript, 2 , Baseline Over "b" , EndFractiony=−ab·x+a·P1b+b·P2b
33
Som det fremgår, har P₁ og P₂
34
erstattet x₀ og y₀ i linjens ligning.
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Punkter
對學生隱藏此資料夾。
36
46
技術支援
技術支援
Start black, left parenthesis, "x" Subscript, 0 , Baseline ; "y" Subscript, 0 , Baseline , right parenthesis equals ( 1 ; negative 1 ) End blackx0;y0=(1;−1)
