นิพจน์ 20: "y" equals "m" Subscript, 1 , Baseline left parenthesis, "x" minus "G" Subscript, 1 , Baseline , right parenthesisy=m1x−G1
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นิพจน์ 21: "y" equals negative StartRoot, "R" squared minus "x" squared , EndRooty=−R2−x2
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นิพจน์ 22: "m" Subscript, 1 , Baseline left parenthesis, "x" minus "G" Subscript, 1 , Baseline , right parenthesis equals negative StartRoot, "R" squared minus "x" squared , EndRootm1x−G1=−R2−x2
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นิพจน์ 23: left parenthesis, "m" squared plus 1 , right parenthesis "x" squared minus 2 "m" squared "G" Subscript, 1 , Baseline "x" plus "m" squared "G" squared minus "R" squared equals 0m21+1x2−2m21G1x+m21G21−R2=0
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นิพจน์ 24: "F" Subscript, 1 , Baseline equals StartFraction, negative "b" plus StartRoot, "b" squared minus 4 "a" "c" , EndRoot Over 2 "a" , EndFractionF1=−b+b2−4ac2a