Sum of alternating addition and subtraction of reciprocal factorials
運算式 2: "k" equals 10k=10
negative 10−10
1010
2
運算式 3: Start sum from "n" equals 1 to 1000, end sum, StartFraction, left parenthesis, negative 1 , right parenthesis Superscript, "n" plus 1 , Baseline "k" Over "n" ! , EndFraction1000∑n=1−1n+1kn!
