運算式 35: quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 1 , right parenthesisquartileData,1
35
運算式 36: quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 2 , right parenthesisquartileData,2
36
運算式 37: quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 3 , right parenthesisquartileData,3
37
運算式 38: "I" Subscript, "q" "r" , Baseline equals quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 3 , right parenthesis minus quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 1 , right parenthesisIqr=quartileData,3−quartileData,1
38
運算式 39: min left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , right parenthesisminData
39
運算式 40: max left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , right parenthesismaxData
40
運算式 41: left parenthesis, quartile left parenthesis, "D" Subscript, "a" "t" "a" , Baseline , 2 , right parenthesis , negative 0.5 , right parenthesisquartileData,2,−0.5
