AP Calculus BC - The Fundamental Theorem of Calculus and Definite Integrals
Primary Input (Function, Interval, Method)
Peitke see kaust õpilaste eest.
8
Avaldis 9: "f" left parenthesis, "x" , right parenthesis equals StartFraction, "x" to the 4th power Over 625 , EndFraction negative StartFraction, 3 "x" squared Over 25 , EndFraction positive 1fx=x4625−3x225+1
9
Avaldis 10: left bracket, "x" Subscript, 1 , Baseline less than or equal to "x" less than or equal to "x" Subscript, 2 , Baseline , right bracketx1≤x≤x2
10
Avaldis 11: "x" Subscript, 1 , Baseline equals negative 5x1=−5
negative 10−10
1010
11
Avaldis 12: "x" Subscript, 2 , Baseline equals 4x2=4
Method = 0 for the definite integral (area under y = 0 is counted as negative)
Method = 1 for area under the curve (area under y = 0 is counted as positive)
15
Visual Representation Construction
Peitke see kaust õpilaste eest.
16
42
toiteallikas
toiteallikas
"x" Subscript, 1 , Baseline equals negative 5x1=−5
"x" Subscript, 2 , Baseline equals 4x2=4
Statistics
Start integral from "x" Subscript, 1 , Baseline to "x" Subscript, 2 , Baseline , end integral, "f" left parenthesis, "x" , right parenthesis "d" "x" equals 2.7 6 8∫x2x1fxdx=2.768
