表达式13: "K" equals left bracket, 0...1 7 , right bracketK=0...17
equals=
00
11
22
33
44
55
66
77
88
99
1010
1111
1212
1313
1414
18个元素列表
13
表达式14: "f" left parenthesis, "x" , right parenthesis equals hyperbolic secant left parenthesis, "x" , right parenthesis left parenthesis, 1 quarter plus 1 half sin left parenthesis, 3 pi tanh left parenthesis, StartFraction, "x" Over 4 , EndFraction , right parenthesis , right parenthesis , right parenthesisfx=sechx14+12sin3πtanhx4
14
表达式15: "C" Subscript, "T" , Baseline equals StartFraction, left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "T" left parenthesis, "K" , "x" , right parenthesis "f" left parenthesis, "x" , right parenthesis NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis Over left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "T" left parenthesis, "K" , "x" , right parenthesis squared NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis , EndFractionCT=∫∞−∞TK,xfx1+x2dx∫∞−∞TK,x21+x2dx
表达式16: "C" Subscript, "U" , Baseline equals StartFraction, left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "U" left parenthesis, "K" , "x" , right parenthesis "f" left parenthesis, "x" , right parenthesis NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis Over left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "U" left parenthesis, "K" , "x" , right parenthesis squared NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis , EndFractionCU=∫∞−∞UK,xfx1+x2dx∫∞−∞UK,x21+x2dx
表达式17: Start sum from "n" equals 0 to "N" , end sum, left parenthesis, "C" Subscript, "T" , Baseline left bracket, "n" plus 1 , right bracket "T" left parenthesis, "n" , "x" , right parenthesis , right parenthesisN∑n=0CTn+1Tn,x
17
表达式18: Start sum from "n" equals 0 to "N" , end sum, left parenthesis, "C" Subscript, "U" , Baseline left bracket, "n" plus 1 , right bracket "U" left parenthesis, "n" , "x" , right parenthesis , right parenthesisN∑n=0CUn+1Un,x
18
You can tweak the weight function in the numerator and then apply the reciprocal of the modified version to change asymptotic behavior or tradeoff error in different intervals (so long as it doesn't break convergence)
19
表达式20: "C" Subscript, "T" 2 , Baseline equals StartFraction, left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "T" left parenthesis, "K" , "x" , right parenthesis "f" left parenthesis, "x" , right parenthesis NestedOver left parenthesis, 1 plus "x" squared , right parenthesis Superscript, left parenthesis, 1 plus "a" , right parenthesis , Baseline , EndNestedFraction "d" "x" , right parenthesis Over left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "T" left parenthesis, "K" , "x" , right parenthesis squared NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis , EndFractionCT2=∫∞−∞TK,xfx1+x21+adx∫∞−∞TK,x21+x2dx
表达式21: "C" Subscript, "U" 2 , Baseline equals StartFraction, left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "U" left parenthesis, "K" , "x" , right parenthesis "f" left parenthesis, "x" , right parenthesis NestedOver left parenthesis, 1 plus "x" squared , right parenthesis Superscript, left parenthesis, 1 plus "a" , right parenthesis , Baseline , EndNestedFraction "d" "x" , right parenthesis Over left parenthesis, Start integral from negative infinity to infinity , end integral, StartNestedFraction, "U" left parenthesis, "K" , "x" , right parenthesis squared NestedOver left parenthesis, 1 plus "x" squared , right parenthesis , EndNestedFraction "d" "x" , right parenthesis , EndFractionCU2=∫∞−∞UK,xfx1+x21+adx∫∞−∞UK,x21+x2dx
表达式23: Start sum from "n" equals 0 to "N" , end sum, left parenthesis, "C" Subscript, "T" 2 , Baseline left bracket, "n" plus 1 , right bracket "T" left parenthesis, "n" , "x" , right parenthesis , right parenthesis left parenthesis, 1 plus "x" squared , right parenthesis Superscript, left parenthesis, "a" , right parenthesis , BaselineN∑n=0CT2n+1Tn,x1+x2a
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表达式24: Start sum from "n" equals 0 to "N" , end sum, left parenthesis, "C" Subscript, "U" 2 , Baseline left bracket, "n" plus 1 , right bracket "U" left parenthesis, "n" , "x" , right parenthesis , right parenthesis left parenthesis, 1 plus "x" squared , right parenthesis Superscript, left parenthesis, "a" , right parenthesis , BaselineN∑n=0CU2n+1Un,x1+x2a
24
Coefficients can also using a truncated fourier transform of f(tan(pi/2*x)) on (-1,1)