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Tank
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Set total volume and diameter, calculate volume at a specific height. x-coordinate is the tank filled height, y-coordinate is the volume
Set total volume and diameter, calculate volume at a specific height. x-coordinate is the tank filled height, y-coordinate is the volume
對學生隱藏此資料夾。
4
運算式 5: "V" Subscript, "t" "o" "t" "a" "l" , Baseline equals 5226.6 7
V
t
o
t
a
l
=
5
2
2
6
.
6
7
0
0
10000
1
0
0
0
0
5
運算式 6: "d" Subscript, "i" "a" "m" "e" "t" "e" "r" , Baseline equals 1.1 7 3 3 1
d
i
a
m
e
t
e
r
=
1
.
1
7
3
3
1
0
0
500
5
0
0
6
運算式 7: "V" Subscript, "o" "l" "u" "m" "e" , Baseline left parenthesis, "h" Subscript, "e" "i" "g" "h" "t" , Baseline , right parenthesis equals StartFraction, 2 "V" Subscript, "t" "o" "t" "a" "l" , Baseline Over pi , EndFraction left parenthesis, StartRoot, StartFraction, "h" Subscript, "e" "i" "g" "h" "t" , Baseline Over "d" Subscript, "i" "a" "m" "e" "t" "e" "r" , Baseline , EndFraction minus left parenthesis, StartFraction, "h" Subscript, "e" "i" "g" "h" "t" , Baseline Over "d" Subscript, "i" "a" "m" "e" "t" "e" "r" , Baseline , EndFraction , right parenthesis squared , EndRoot left parenthesis, StartFraction, 2 times "h" Subscript, "e" "i" "g" "h" "t" , Baseline Over "d" Subscript, "i" "a" "m" "e" "t" "e" "r" , Baseline , EndFraction minus 1 , right parenthesis plus arcsin left parenthesis, StartRoot, StartFraction, "h" Subscript, "e" "i" "g" "h" "t" , Baseline Over "d" Subscript, "i" "a" "m" "e" "t" "e" "r" , Baseline , EndFraction , EndRoot , right parenthesis , right parenthesis
V
o
l
u
m
e
h
e
i
g
h
t
=
2
V
t
o
t
a
l
π
h
e
i
g
h
t
d
i
a
m
e
t
e
r
−
h
e
i
g
h
t
d
i
a
m
e
t
e
r
2
2
·
h
e
i
g
h
t
d
i
a
m
e
t
e
r
−
1
+
a
r
c
s
i
n
h
e
i
g
h
t
d
i
a
m
e
t
e
r
7
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Visual controls
對學生隱藏此資料夾。
8
15
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At height 0.363m, volume is 1376.24 liters
Diameter 1.17331m, Total Volume 5226.67 liters
"x"
x
"y"
y
"a" squared
a
2
"a" Superscript, "b" , Baseline
a
b
7
7
8
8
9
9
over
÷
功能
(
(
)
)
less than
<
greater than
>
4
4
5
5
6
6
times
×
| "a" |
|
a
|
,
,
less than or equal to
≤
greater than or equal to
≥
1
1
2
2
3
3
negative
−
A B C
StartRoot, , EndRoot
pi
π
0
0
.
.
equals
=
positive
+
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