นิพจน์ 9: polygon left parenthesis, "A" , "B" , right parenthesispolygonA,B
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นิพจน์ 10: polygon left parenthesis, "C" , "D" , right parenthesispolygonC,D
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นิพจน์ 11: "y" equals "x"y=x
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`m_1=\frac{b-\sqrt{ab}}{b-a}` "M" Subscript, 1 , Baseline equals StartFraction, left parenthesis, "A" plus "B" , right parenthesis Over 2 , EndFractionM1=A+B2
ป้ายกำกับ:
equals=
left parenthesis, 0.9 3 6 5 , 1.0 9 4 6 2 4 5 4 , right parenthesis0.9365,1.09462454
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`m_2=\frac{\sqrt{ab}-a}{b-a}` "M" Subscript, 2 , Baseline equals StartFraction, left parenthesis, "C" plus "D" , right parenthesis Over 2 , EndFractionM2=C+D2
ป้ายกำกับ:
equals=
left parenthesis, 0.9 3 6 5 , 0.6 8 3 1 2 4 5 4 , right parenthesis0.9365,0.68312454
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นิพจน์ 14:
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ดำเนินการโดย
ดำเนินการโดย
"A" ( "a" , StartRoot, "a" "b" , EndRoot )A(a,ab)
"B" ( "b" , "b" )B(b,b)
"C" ( "a" , "a" )C(a,a)
"D" ( "b" , StartRoot, "a" "b" , EndRoot )D(b,ab)
"m" Subscript, 1 , Baseline equals StartFraction, "b" minus StartRoot, "a" "b" , EndRoot Over "b" minus "a" , EndFractionm1=b−abb−a
"m" Subscript, 2 , Baseline equals StartFraction, StartRoot, "a" "b" , EndRoot minus "a" Over "b" minus "a" , EndFractionm2=ab−ab−a
