since dg(x)/dn is 0 at the "midpoint" of g(x), it means that changing n does not change the y value
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t(x) us the slope, and v(x) shows how the slope will change in regards to changing n -> this is correct because as n is increased the slope decreases
13
y_max= a
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y_min = b
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negative 10
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negative 10
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negative 10
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negative 10
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