trick: force searching solutions away from the previous one
6
Expression 7: "x" Subscript, 1 , Baseline equals "x" Subscript, 0 , Baseline minus 5 plus "d" Subscript, 1 , Baseline equals negative 1.2 3 0 7 0 6 7 2 9 3 2x1=x0−5+d1
equals=
negative 1.2 3 0 7 0 6 7 2 9 3 2−1.23070672932
7
Expression 8: "x" Subscript, 2 , Baseline equals "x" Subscript, 1 , Baseline minus 5 plus "d" Subscript, 2 , Baseline equals negative 1.2 3 0 7 0 6 7 2 9 3 2x2=x1−5+d2
equals=
negative 1.2 3 0 7 0 6 7 2 9 3 2−1.23070672932
8
alternate attempt to separate solutions (not working)
9
Expression 10: " left bracket, "P" left parenthesis, "x" Subscript, 0 , Baseline , right parenthesis , "P" left parenthesis, "x" Subscript, 1 , Baseline , right parenthesis left brace, "x" Subscript, 1 , Baseline less than "x" Subscript, 0 , Baseline minus epsilon , right brace , "P" left parenthesis, "x" Subscript, 2 , Baseline , right parenthesis left brace, "x" Subscript, 2 , Baseline less than "x" Subscript, 1 , Baseline minus epsilon , right brace , right bracket tilde 0 Sorry, I don't understand the '"' symbol."Px0,Px1x1<x0−ϵ,Px2x2<x1−ϵ~0
10
Expression 11: epsilon equals 10 to the negative 4th power equals 0.0 0 0 1ϵ=10−4
