運算式 13: StartFraction, left parenthesis, left parenthesis, "x" minus "h" Subscript, 2 , Baseline , right parenthesis cos left parenthesis, "l" Subscript, 2 , Baseline , right parenthesis minus left parenthesis, "y" minus "k" Subscript, 2 , Baseline , right parenthesis sin left parenthesis, "l" Subscript, 2 , Baseline , right parenthesis minus "f" Subscript, 2 , Baseline , right parenthesis squared Over "a" squared , EndFraction plus StartFraction, left parenthesis, left parenthesis, "x" minus "h" Subscript, 2 , Baseline , right parenthesis sin left parenthesis, "l" Subscript, 2 , Baseline , right parenthesis plus left parenthesis, "y" minus "k" Subscript, 2 , Baseline , right parenthesis cos left parenthesis, "l" Subscript, 2 , Baseline , right parenthesis , right parenthesis squared Over "b" squared , EndFraction equals 1x−h2cosl2−y−k2sinl2−f22a22+x−h2sinl2+y−k2cosl22b22=1
13
隱藏的 標籤 left parenthesis, "h" Subscript, 2 , Baseline , "k" Subscript, 2 , Baseline , right parenthesish2,k2
標籤
equals=
left parenthesis, 151.3 1 5 9 6 4 , 42.8 3 6 3 2 0 9 , right parenthesis151.315964,42.8363209
運算式 17: "h" Subscript, 2 , Baseline equals "a" cosine left parenthesis, "l" plus "t" , right parenthesis cosine left parenthesis, "l" , right parenthesis plus "f" cosine left parenthesis, "l" , right parenthesis plus "b" sine left parenthesis, "l" plus "t" , right parenthesis sine left parenthesis, "l" , right parenthesish2=acosl+tcosl+fcosl+bsinl+tsinl
equals=
151.3 1 5 9 6 4 1 0 1151.315964101
17
運算式 18: "k" Subscript, 2 , Baseline equals "a" cosine left parenthesis, "l" plus "t" , right parenthesis sine left parenthesis, "l" , right parenthesis minus "f" sine left parenthesis, "l" , right parenthesis minus "b" sine left parenthesis, "l" plus "t" , right parenthesis cosine left parenthesis, "l" , right parenthesisk2=acosl+tsinl−fsinl−bsinl+tcosl
equals=
42.8 3 6 3 2 0 9 4 1 942.8363209419
18
運算式 19: "a" Subscript, 2 , Baseline equals "O" Subscript, 2 , Baseline left parenthesis, 1 plus "E" squared , right parenthesisa2=O21+E22
equals=
2020
19
運算式 20: "b" Subscript, 2 , Baseline equals "O" Subscript, 2 , Baseline left parenthesis, 1 minus "E" squared , right parenthesisb2=O21−E22
equals=
2020
20
運算式 21: "f" Subscript, 2 , Baseline equals StartRoot, "a" squared minus "b" squared , EndRootf2=a22−b22
